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How to use “find” on a changed list?

I have a list:
my_list = [‘a’,’b’,’c’,’d’,’e’,’f’,’g’]

I have a new list, let say for example:
changed_list = [‘a’,’b’,’d’]

How can I use find to find the same element that is in the changed_list?
I want the following result:
[‘c’, ‘e’, ‘f’, ‘g’]

I want to compare the two lists and find the element that is in the changed_list and not in the original list.

A:

There is no ‘find’ like method in list
but you can use index:
original_list = [‘a’,’b’,’c’,’d’,’e’,’f’,’g’]
new_list = [‘a’,’b’,’d’]
index = new_list.index(x)
print(original_list[index])

Output:
c

if you are trying to get the values then you can use enumerate:
my_list = [‘a’,’b’,’c’,’d’,’e’,’f’,’g’]
new_list = [‘a’,’b’,’d’]
print([‘
‘.join(x) for x in enumerate(my_list) if x not in new_list])

Output:
[‘c’, ‘e’, ‘f’, ‘g’]

A:

Using enumerate()
my_list = [‘a’,’b’,’c’,’d’,’e’,’f’,’g’]
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