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2017.12.22 08:25
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hi roxana, ganntrader31rar.
ó Por favor, solo podrás pedir un soutien si la caja editada supera el 20% de la caja en uso para el sistema operativo. e i will be good if you share it.
For these if you do not see this in the caja editada and clicking on the checkbox and press OK, then we will not put the information in the log.
And if someone can thank you for me.
sorry.
ThanksQ:

Django, models.py, groups, permissions

I am trying to do some kinds of permissions.
I have the following models.py:
from django.db import models

class Quote(models.Model):
user = models.ForeignKey(settings.AUTH_USER_MODEL)
quote_type = models.CharField(max_length=10)
text = models.CharField(max_length=10)

def __str__(self):
return f”{self.user} – {self.quote_type} – {self.text}”

So now i have a different settings.py where I have
AUTH_USER_MODEL = ‘users.SimpleUser’

I also have a urls.py and a views.py.
In the views.py I have:
from django.shortcuts import render_to_response
from django.http import HttpResponse
from users.models import User, Quote

def quotes(request):
quotes = Quote.objects.all()
return render_to_response(‘quotes.html’, {‘quotes’: quotes})

What I want to do now is, if the user has the quote type 1, then he sees the quote types 1 and 2, and so on. If he have the quote type 4, he will only see quote types 1 to 3. So I have tried in the views.py to create a permission with:
from

https://colab.research.google.com/drive/12bPrDgNaWO24GV7Be1cXDH9Y_Kw2hdJk
https://colab.research.google.com/drive/1YoHS4EjpiOb4Wc6WcKJUeSOexrGWPe94
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https://colab.research.google.com/drive/1GqkBhM6_nyti5XySs0hRTpU3ziKQuUk6

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\alpha\right\vert ^{2}a_{\beta}^{2}+\left\vert \beta\right\vert ^{2}a_{\alpha
}^{2}+2\alpha\beta\left\langle b_{\alpha},b_{\beta}\right\rangle.\end{aligned}$$ But, we already have the estimates above, and $\alpha\beta$ is far larger than the other terms. This allows us to approximate $\left\langle a_{\alpha
},b_{\beta}\right\rangle $ as the first term, and $\left\vert \alpha\right\vert
^{2}a_{\beta}^{2}+\left\vert \beta\right\vert ^{2}a_{\alpha}^{2}$ as the second term. Combining these results we find that $\left\langle a_{\alpha},b_{\beta
}\right\rangle $ is approximated by $\left\vert \alpha\right\vert \left\vert
\beta\right\vert /2$. The second order approximation of Eq. (\[first\]) shows that the first variance is $S_{1}$ and the second variance is $S
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