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A standard dc motor is described that uses a 4-pole electro-mechanical winding. If the winding is tapped at the n 1th, n 4th, and n 5th turns, then the rpm is n 1/2 P / 1. The voltage V 1 = 120V divided by âV 1/2 P / 1Â â gives the stall torque âT 1/2 P / 1Â â. The stall current i 1 is given by 4 e V 1 / ( R 1 1 V ) which is â120 V / 120â or â1â. The winding resistance R 1 is obtained from the ratio of V â2â divided by the rpm divided by i 1. The current i 2 flowing into the winding is V â2â/ ( n 2 rp ) = â120 V / 1â or â120â. To find the resistance r 2 of the winding, V 1 is divided by i 2. It follows that r 2 = V 1 â2â â120â â V 1 â2â / i 1 = â120 V / 120â â120â â 120 V â2â â120â â 120 V â2â / 120 = â120â / 120 = 1/120 or â1. 2ââ = 1/120 * r 2 = 1. 2 1. 2
If the four-pole winding is made by a standard dc motor, three poles, which form a winding of only three turns, are used, connected in series. If the winding is tapped at the first, third, and fifth turns, the rpm is P / 2.
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