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I did my engineering in civil and So it’s been two-and-a-half years since then. So I’m very much different from. Abbreviations for specific times can be found here. The word first appeared in English in 1406 and the earliest use of the word time in English is in the year 1400. The new year on the Hebrew calendar begins on the evening of the new moon following the spring equinox. In 2017, years beginning on Saturday, June 29 or later will contain 354 days, 5 hours, and 45 minutes. Tuesday, October 25, 2017, at 08:30:18 PM CDT. The post-Gutenberg era began on January 1, 1501, and lasted until Johann Gutenberg gave up his printing press in October 1476. The 16th century was a period of intellectual ferment comparable to the period of the Scientific Revolution in Europe, and the Reformation and Counter-Reformation in Europe and Europe. It represents the idea that one can achieve a golden mean or balance between one’s work and playtime. This originates from ancient China and the idea of the Mean. It is one of the four classical elements along with: earth, water, fire, and wind.

Every day the measure of time passed until this year when we suddenly got a reminder of the ring when Shota came to Ulysse. He also remarked that the time will be shortened by three hours. Julian. In the Julian calendar, the first day of the year is the same as the vernal equinox which occurs on March 21 in the modern Gregorian calendar.

Next, he says, will come a period of great darkness, where there will be no sun during “a thousand years. ” In the end of days, Sunagawa says, there will

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Find the limit of $(0.5(a_n+1/n))/(0.5(a_n+1/n)+1)$

I am having some trouble solving limits.
I am trying to find $\lim_{n \to \infty} \dfrac{0.5(a_n+1/n)}{0.5(a_n+1/n)+1}$, where $a_n=\dfrac{1}{n^2}$.
The numerator tends to $0$ and the denominator tends to $0$. From the definition of limits I know that $\lim_{n \to \infty} a_n=0$, but I am stuck.
How can I find the limit using the definition?

A:

Note that
$$
\lim_{n\rightarrow\infty} \dfrac{0.5(a_n+1/n)}{0.5(a_n+1/n)+1}
=\lim_{n\rightarrow\infty} \dfrac{0.5+\frac{1}{2n^2}}{0.5+\frac{1}{2n^2}+1}
$$
On the right hand side, for $n$ large, the second term dominates, and so we have
$$
\lim_{n\rightarrow\infty} \dfrac{0.5+\frac{1}{2n^2}}{0.5+\frac{1}{2n^2}+1} = \frac{1}{2}
$$
Which is just the definition of $\lim_{n\rightarrow\infty} a_n=0$.

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