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A:

Thanks to @flarnov and @blackjama – the idea of @flarnov is correct.
I have written the solution below.
When you want to login to gmail without an account, you will have to go to Google dashboard, and click on “Forgot Password”, and then you will have to enter the user name, and the email associated to this user. Google will ask you for a code that you will have to enter to link it to the email address.
After that, you will be able to login with your user name and the link.
Below is the user name and the link that was automatically generated by Google:
Enter your user name and the email associated to this user:
Enter your email in the box below to get code:
Enter the code :

Keep this code in mind! After you have entered the link above, you can change the email to an account with your own email, so the link will not be valid anymore. Then you will have to create a new one with the code you have.
This could be a good solution for people that want to login to an email without an account.

Q:

When are Markov chains ergodic?

Let $S$ be a finite, alphabet-symbol set. Let $q$ be an element in $\mathbb{R}^S$, and let $P$ be a $q$-dependent Markov chain, i.e. $P(x,A)=\sum_y P(y,A|x)q(y)$. (I know this is not standard, but for my purposes it is not a problem.)
I am interested in when $P$ is ergodic. What can be said about the structure of the probability vector $q$ in order to guarantee ergodicity?

A:

We have that, if $q$ is strictly positive in every state, then $P$ is ergodic. Indeed, in every state we have $P_t P_{t+1}=P_t$, hence also
$$
P_t q_x=P_t (\sum_y q(y)P(y,\cdot|x)) =\sum_y q(y)P_t
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